Abstract
Let $A$ be an irreducible nonnegative matrix, $w$ be any of its indices, and $A-w$ be the
principal submatrix of co-order one obtained from $A$ by deleting the $w$th column and row.
Denote by $V_ext(A)$ the set of indices $w$ such that $A − w$ has the biggest Perron root (among all the principal submatrices of co-order one of the original matrix $A$). We prove that exactly one Jordan block corresponds to the Perron root $λ(A − w)$ of $A − w$ for every $w V_ext(A)$.
If its size is strictly greater than one for some w ∈ Vext(A), then the original matrix A is permutationally
similar to a lower Hessenberg matrix with positive entries on the superdiagonal
and in the left lower corner (in other words, the digraph D(A) of A has a Hamiltonian circuit
and its diameter is one less than its order). In the opposite case for any w ∈ Vext(A), there is
a unique path γ = wi
p
i=0 going through w in D(A) such that
(1) A − wi has the biggest Perron root for i = 0,...,p;
(2) A − w0 has a right positive Perron eigenvector;
(3) A − wp has a left positive Perron eigenvector;
(4) A − wi has neither a left nor a right positive Perron eigenvector for i = 1,...,p − 1.
Thus, by the spectral criterion for a nonnegative matrix to be irreducible, the submatrices
A − w0,...,A − wp combined inherit the property of irreducibility. We also show that
A − w is irreducible for every w ∈ Vext(A) if any of the following holds:
(1) A is symmetric;
(2) every column (row) of A has at least two positive nondiagonal entries;
If A is an irreducible tournament matrix, then either A − w is also irreducible for any
w ∈ Vext(A) or there exist exactly two indices w_in and w_out in Vext(A) such that A − win
and A − wout are reducible. In the last case any other principal submatrix of co-order one is
irreducible. This shows that in the general case, a one-vertex-deleted subdigraph with the biggest
Perron root need not have the best connectivity properties among all one-vertex-deleted
subdigraphs of a given strongly connected digraph D.
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